To solve the system of differential equations
(1)
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where is a matrix and and are vectors, first consider the homogeneous case with . The solutions to
(2)
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are given by
(3)
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But, by the eigen decomposition theorem, the matrix exponential can be written as
(4)
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where the eigenvector matrix is
(5)
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and the eigenvalue matrix is
(6)
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Now consider
(7)
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(8)
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(9)
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The individual solutions are then
(10)
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so the homogeneous solution is
(11)
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where the s are arbitrary constants.
The general procedure is therefore
1. Find the eigenvalues of the matrix (, ..., ) by solving the characteristic equation.
2. Determine the corresponding eigenvectors , ..., .
3. Compute
(12)
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for , ..., . Then the vectors which are real are solutions to the homogeneous equation. If is a matrix, the complex vectors correspond to real solutions to the homogeneous equation given by and .
4. If the equation is nonhomogeneous, find the particular solution given by
(13)
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where the matrix is defined by
(14)
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If the equation is homogeneous so that , then look for a solution of the form
(15)
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This leads to an equation
(16)
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so is an eigenvector and an eigenvalue.
5. The general solution is
(17)
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