To solve the system of differential equations
(1)
|
where is a matrix and
and
are vectors, first consider the
homogeneous case with
. The solutions to
(2)
|
are given by
(3)
|
But, by the eigen decomposition theorem, the matrix exponential can be written as
(4)
|
where the eigenvector matrix is
(5)
|
and the eigenvalue matrix is
(6)
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Now consider
(7)
| |||
(8)
| |||
(9)
|
The individual solutions are then
(10)
|
so the homogeneous solution is
(11)
|
where the s are arbitrary constants.
The general procedure is therefore
1. Find the eigenvalues of the matrix (
, ...,
) by solving the characteristic
equation.
2. Determine the corresponding eigenvectors , ...,
.
3. Compute
(12)
|
for , ...,
. Then the vectors
which are real are solutions
to the homogeneous equation. If
is a
matrix, the complex
vectors
correspond to real solutions
to the homogeneous equation given by
and
.
4. If the equation is nonhomogeneous, find the particular solution given by
(13)
|
where the matrix is defined by
(14)
|
If the equation is homogeneous so that , then look for a solution of
the form
(15)
|
This leads to an equation
(16)
|
so is an eigenvector and
an eigenvalue.
5. The general solution is
(17)
|