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Nephroid Involute

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NephroidInvolute

The involute of the nephroid given by

x=1/2[3cost-cos(3t)]
(1)
y=1/2[3sint-sin(3t)]
(2)

beginning at the point where the nephroid cuts the y-axis is given by

x=4cos^3t
(3)
y=3sint+sin(3t),
(4)

another nephroid. If the involute is begun instead at the cusp, the result is Cayley's sextic.

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Cite this as:

Weisstein, Eric W. "Nephroid Involute." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/NephroidInvolute.html

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