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Hasse-Davenport Relation


Let F be a finite field with q elements, and let F_s be a field containing F such that [F_s:F]=s. Let chi be a nontrivial multiplicative character of F and chi^'=chi degreesN_(F_s/F) a character of F_s. Then

 (-g(chi))^s=-g(chi^'),

where g(x) is a Gaussian sum.


See also

Gaussian Sum, Multiplicative Character

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References

Ireland, K. and Rosen, M. "A Proof of the Hasse-Davenport Relation." §11.4 in A Classical Introduction to Modern Number Theory, 2nd ed. New York: Springer-Verlag, pp. 162-165, 1990.

Referenced on Wolfram|Alpha

Hasse-Davenport Relation

Cite this as:

Weisstein, Eric W. "Hasse-Davenport Relation." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/Hasse-DavenportRelation.html

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