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Circle Inscribing


If r is the inradius of a circle inscribed in a right triangle with sides a and b and hypotenuse c, then

 r=1/2(a+b-c).
(1)
CircleCircleTriangle

A Sangaku problem dated 1803 from the Gumma Prefecture asks to construct the figure consisting of a circle centered at O, a second smaller circle centered at O_2 tangent to the first, and an isosceles triangle whose base AB completes the diameter of the larger circle through the smaller XB. Now inscribe a third circle with center O_3 inside the large circle, outside the small one, and on the side of a leg of the triangle. It then follows that the line O_3A_|_XB. To find the explicit position and size of the circle, let the circle O have radius 1/2 and be centered at (0,0) and let the circle O_2 have diameter 0<r<1. Then solving the simultaneous equations

 (1/2r+a)^2=(1/2r)^2+y^2
(2)
 (1/2-a)^2=(r-1/2)^2+y^2
(3)

for a and y gives

a=(r(1-r))/(1+r)
(4)
y=(rsqrt(2(1-r)))/(1+r).
(5)

See also

Incircle, Inscribed, Polygon

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References

Rothman, T. "Japanese Temple Geometry." Sci. Amer. 278, 85-91, May 1998.

Referenced on Wolfram|Alpha

Circle Inscribing

Cite this as:

Weisstein, Eric W. "Circle Inscribing." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/CircleInscribing.html

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